Ch.11 Questions 42,42,44(1-3)

These are questions that I did for chemistry to improve me being able to find out the percent of an element in a compound.

1. Calcium Chloride
1. first i find the atomic mass of each compound(Ca and Cl)
1. Ca=40.08
2. Cl=35.45
2. Now since there are two Cl we 35.35x2=70.9
3. we than add 70.9+40.08=110.98
4. CaCl2 has a mass of 110.98
1. to find out the percent of Ca and Cl we simply divide the individual mass by the total mass
1. 40.08/110.98=36.11%
2. 70.9/110.98=63.88%
2. Sodium Sulfate
1. find the total mass of Sodium Sulfate
1. Na2So4
1. Na=22.990x2=45.980
2. S=32.066
3. O=15.999x4=63.996
2. add all the individual masses together
1. Na2SO4=142.042
3. divide each individual mass by the total
1. Na(45.980/142.042=32.37%)
2. S(32.066/142.042=22.58%)
3. O(63.996/142.042=45.05%)
3. Which has a larger % of Sulfur H2SO3 or H2S2O8
1. find the total mass of 
1. H2SO3
1. H=1x2=2
2. S=32.066
3. O=15.999x3=47.997
2. add all the individual masses together
1. H2SO3=82.063
3. divide each individual mass by the total
1. S(32.066/82.063=39%)
4. find the total mass of
1. H2S2O8
1. H=1x2=2
2. S=32.066x2=64.132
3. O=15.999x8=127.992
5. add all the individual masses together
1. H2S2O8=194.124
6. divide each individual mass by the total
1. S(64.132/194.124=33.03%)

H2SO3 has a larger sulfur percent.